Subject: Re: [xsl] How to assign a sequence to a variable? From: Manfred Staudinger <manfred.staudinger@xxxxxxxxx> Date: Tue, 9 Aug 2005 16:03:43 +0200 |
> You need as item()+ on the variable definition, eg: > > <xsl:variable name="tempb" as="item()+"> Sorry, this does not seem to change anythinghelp on my test case. Manfred On 8/9/05, andrew welch <andrew.j.welch@xxxxxxxxx> wrote: > > Hi list, > > I would like to return a sequence from a named > > template, but I'm only getting a single string. > > In the test only tempa gets the sequence, but how > > to get it work for tempb and tempc? > > > > <?xml version="1.0" encoding="UTF-8" ?> > > <xsl:stylesheet version="2.0" > > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="/"> > > <xsl:variable name="tempa" select="'a1','a2','a3'"/> > > <xsl:message select="$tempa[3]"/> > > <xsl:variable name="tempb"> > > <xsl:value-of select="'b1','b2','b3'"/> > > </xsl:variable> > > <xsl:message select="$tempb[1]"/> > > <xsl:variable name="tempc"> > > <xsl:call-template name="processName"> > > </xsl:call-template> > > </xsl:variable> > > <xsl:message select="$tempc[1]"/> > > </xsl:template> > > <xsl:template name="processName"> > > <xsl:value-of select="'c1','c2','c3'"/> > > </xsl:template> > > </xsl:stylesheet> > > You need as item()+ on the variable definition, eg: > > <xsl:variable name="tempb" as="item()+"> > .... > > Otherwise you will get a tree with a single child text node with all > the entries in the sequence concatenated together with a space between > each. > > cheers > andrew
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