Subject: Re: [xsl] Sorted node set and following-sibling axis From: JBryant@xxxxxxxxx Date: Wed, 10 Aug 2005 13:42:43 -0500 |
Hi, Nick, How do you determine which values go in which divs? That is, what is the logic behind the grouping? It appears to two to a div, but it's hard to tell with a small data sample. If you do just want to a div element around every pair of values, that's pretty straightforward: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:variable name="articles"> <xsl:for-each select="/articles/article"> <xsl:sort select="@priority" data-type="number" order="descending"/> <p><xsl:value-of select="."/></p> </xsl:for-each> </xsl:variable> <xsl:template match="articles"> <xsl:for-each select="$articles/p"> <xsl:if test="position() mod 2 = 1"> <div> <xsl:copy-of select="."/> <xsl:if test="following-sibling::*[1]"> <xsl:copy-of select="following-sibling::*[1]"/> </xsl:if> </div> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> The notion is to first get a list of sorted p elements, which you can then stuff into whatever logic you need for div elements. In this case, I just grouped them as pairs (as your output showed). Speaking of output, here's what Saxon 8.5 gave me: <div> <p> first </p> <p> second </p> </div> <div> <p> third </p> <p> last </p> </div> Jay Bryant Bryant Communication Services (presently consulting at Synergistic Solution Technologies) "Nick Fitzsimons" <nick@xxxxxxxxxxxxxx> 08/10/2005 12:11 PM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx To xsl-list@xxxxxxxxxxxxxxxxxxxxxx cc Subject [xsl] Sorted node set and following-sibling axis Hi, I've got a problem which I think may be beyond the powers of XSLT 1, but maybe somebody can help me out. The simplified structure of the data is as follows: <articles> <article priority="3"> <title>second</title> </article> <article priority="9"> <title>first</title> </article> <article priority="1"> <title>last</title> </article> <article priority="3"> <title>third</title> </article> </articles> and I need to output it sorted on the "priority" attribute. Note that a) a higher value of priority is sorted to the top of the output (descending sort); b) some articles have the same priority, in which case they are output in source order; c) values for priority are not necessarily contiguous. There isn't a problem in the simple case: <xsl:template match="articles"> <xsl:apply-templates select="article"> <xsl:sort select="@priority" data-type="number" order="descending" /> </xsl:apply-templates> </xsl:template> <xsl:template match="article> <p><xsl:value-of select="title" /></p> </xsl:template> will give <p>first</p> <p>second</p> <p>third</p> <p>last</p> However, what I require is the following: <div> <p>first</p> <p>second</p> </div> <div> <p>third</p> <p>last</p> </div> The problem is that something like the following won't work: <xsl:template match="article> <div> <p><xsl:value-of select="title" /></p> <p><xsl:value-of select="following-sibling::article/title" /></p> </div> </xsl:template> as the following-sibling axis returns the nodes in original document order, not sorted order. Any suggestions as to how I can achieve the desired output would be appreciated. (Unfortunately, the obvious solution of converting the data so that the article elements are sorted before I get my hands on it won't work, as this is legacy data, and the idea is precisely to avoid having to do that... something to do with saving money on the back end.) Thanks in advance for any suggestions, Nick. -- Nick Fitzsimons http://www.nickfitz.co.uk/
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