Subject: [xsl] Re: Converting <xml> StyleSheet param contents into a node set? From: Jacquo Johnson <genxgeek@xxxxxxxxx> Date: Wed, 17 Aug 2005 00:38:21 -0600 |
Well, I spoke too soon on this. For some reason the returned nodeset() or lack there of won't let me traverse the tree accordingly: ... Stylesheet: ( Filter=<Node><Value/>HI</Value></Node> ) ... <xsl:param name="Filter" select="0" /> <xsl:variable name="rtf"> <xsl:value-of select="$Filter" disable-output-escaping="yes"/> </xsl:variable> <xsl:variable name="rtf2" select="xalan:nodeset($rtf)" /> <xsl:for-each select="($rtf2)/Value"> <!-- Not returning Value here?? --> <xsl:element name="IncomingValue"> <xsl:copy-of select="."/> </xsl:element> </xsl:for-each> Does anybody have an idea as to what I'm doing wrong here? Thanks in advance! On 8/17/05, Jacquo Johnson <genxgeek@xxxxxxxxx> wrote: > Looks like this works (since I'm pigeon holed using xalan).. > ... > <xsl:variable name="rtf"> > <xsl:value-of select="$Filter" disable-output-escaping="yes"/> > </xsl:variable> > > <xsl:copy-of select="xalan:nodeset($rtf)" /> > ... > > Is there a better way to do this than with xalan:nodeset() or any > equivalent node-set()/nodeset() entension function? > > -- > On 8/16/05, Jacquo Johnson <genxgeek@xxxxxxxxx> wrote: > > HI all, can somebody tell me how I can pass <xml> contents into a > > stylesheet param and then convert that <xml> contents into a nodeset? > > > > > > Stylesheet: ( Filter=<Node><Whatever/></Node> ) > > ... > > <xsl:param name="Filter" select="string('NULL')" /> > > > > <xsl:copy-of select="$Filter"/> > > ... > > Output: > > <Node><Whatever/></Node> > > > > However, I want to turn the xml contents above into a node set that I > > can later use in the transform. Is that possible (is there something > > other than using CDATA)? > > > > Any information would be greatly appreciated.
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