Subject: RE: [xsl] Converting XML to XML From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 17 Aug 2005 12:37:24 +0100 |
Your stylesheet probably doesn't need to declare this namespace, so just delete it: it's needed only when the target vocabulary is XSL-FO, but some XSLT editors seem to declare it for you by default. If you do need a namespace in your stylesheet that you don't want copied into the result document, use the exclude-result-prefixes attribute to exclude it. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: ChandraShekar, A [mailto:ChandraShekar.A@xxxxxxxxxxx] > Sent: 17 August 2005 12:17 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] Converting XML to XML > > Hello, > > I have written small program to convert XML to XML. > But each XML tag contains > xmlns:fo="http://www.w3.org/1999/XSL/Format" as a attribute. How to > avoid this? > > > -----Original Message----- > From: Michael Kay [mailto:mike@xxxxxxxxxxxx] > Sent: Wednesday, August 17, 2005 4:40 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] Converting XML to XML > > > > > > Is it possible to convert XML to XML using XSLT ? > > Yes, that's precisely what XSLT does. > > > > > In my case Source is : > > <a> > > <b> > > </b> > > <c> > > </c> > > </a> > > > > Destination is : > > > > <x> > > <y> > > </y> > > <z> > > </z> > > </x> > > > > Please provide me some sample code. > > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="a"> > <x><xsl:apply-templates/></x> > </xsl:template> > > <xsl:template match="b"> > <y><xsl:apply-templates/></y> > </xsl:template> > > <xsl:template match="c"> > <z><xsl:apply-templates/></z> > </xsl:template> > > </xsl:stylesheet> > > > Michael Kay > http://www.saxonica.com/
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