RE: [xsl] concat all items in a sequence

[<Jarno.Elovirta@xxxxxxxxx>]

Hi

> I'm using the following:
>
> contains(elem, val)
>
> It's possible that 'elem' can be a sequence of more than one item.
>
> The way I've code around this is to use string-join with an empty
> string as one of the arguments:
>
> contains(string-join(for $i in elem return $i, ''), val)
>
> Is there a better way?

E.g.

  some $i in elem satisfies contains($i, val)

Cheers,

Jarno

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