Subject: RE: [xsl] Navigating an XML file with xsl:for-each etc. From: "Khorasani, Houman" <houman_khorasani@xxxxxxxxxxxxxx> Date: Tue, 30 Aug 2005 17:01:00 +0100 |
Many thanks Michael, it works. Now I understand how to navigate the pointers through the current node and the node I searched for. Regards Houman -----Original Message----- From: Michael Kay [mailto:mike@xxxxxxxxxxxx] Sent: 26 August 2005 17:58 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] Navigating an XML file with xsl:for-each etc. > So I have to check what are inside the "add" and compare them > one by one > against those under "delete". If equal then output. I tried > to explain > it better in my shopping list example. :) > > Do you think such a generic thing is possible? Yes, it's entirely possible, but you still haven't given a very precise specification. For example if there are two identical elements under "add" do you require exactly two matching elements under "delete"? Or at least two? Or is one enough? You could start with something like <xsl:for-each select="add/*"> <xsl:if test="../../delete/*[name()=current()/name()]"> ... there's a match ... </xsl:if> </xsl:for-each> Michael Kay http://www.saxonica.com/
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