Subject: Re: [xsl] XSL Unique values From: "Joris Gillis" <roac@xxxxxxxxxx> Date: Wed, 31 Aug 2005 22:59:23 +0200 |
Is there any way using XSL I can get the unique metadata[@fieldid=3]/fieldvalues for each product. I know I can do it across the entire XML doc. In this example for product(name=shirt) it would be RG,LN and SM , product(name=t-shirt) it would be AA,BB,CC,DD,EE. I want to be able to get these separately for each product and iterate through it within the product if possible.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:key name="metadata" match="metadata" use="concat(generate-id(ancestor::product),@fieldid,fieldvalue)"/>
<xsl:template match="product"> <xsl:value-of select="name"/>:
<xsl:for-each select=".//metadata[generate-id( key('metadata',concat(generate-id(current()),3,.))[1])=generate-id()]"> <xsl:value-of select="fieldvalue"/>- </xsl:for-each> </xsl:template>
regards, -- Joris Gillis (http://users.telenet.be/root-jg/me.html) B+Numquam mores quos extuli referoB; - Seneca , Ad Lucilium I, 7
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