Re: [xsl] Get value from update.xml and stored in source.xml(update source.xml)

["Joris Gillis" <roac@xxxxxxxxxx>]

On Wed, 08 Sep 2004 11:40:56 +0200, Shailesh <> wrote:

> I have used posted xml and xslt.
> I have written a small code in VB.NET which takes input as "xml" file and
> for transformation "xslt" and does the transformation which will output  
> an xml file.


What version of msxml do you use?

Please run this diagnosing stylesheet and post the output.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";  
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:output method="xml" indent="yes"/>

<xsl:variable name="update" select="document('update.xml')"/>
<xsl:key name="id" match="*" use="@id"/>

<xsl:template match="/">
<test>
	<source.xml>
		<xsl:copy-of select="/"/>
	</source.xml>
	<source.xml>
		<xsl:copy-of select="$update"/>
	</source.xml>
	<output>
		<xsl:apply-templates/>
	</output>
</test>
</xsl:template>


<xsl:template match="*[@id]">
	<xsl:variable name="id" select="@id"/>
	<xsl:copy>
		<xsl:apply-templates select="@*" />
		<xsl:comment>Looking up <xsl:value-of select="local-name()"/> (id =  
'<xsl:value-of select="@id"/>')</xsl:comment>
		<xsl:comment>With raw xpath:</xsl:comment>
		<xsl:copy-of select="$update//*[@id=$id]/*"/>
		<xsl:comment>With a key:</xsl:comment>
		<xsl:for-each select="$update">
			<xsl:copy-of select="key('id',$id)/*"/>
		</xsl:for-each>
	</xsl:copy>
</xsl:template>

<xsl:template match="node()|@*">
	<xsl:copy>
		<xsl:apply-templates select="node()|@*" />
	</xsl:copy>
</xsl:template>

</xsl:stylesheet>

--
"NN= N?N/N4N1 OON9 N?ON4N-N= N?N/N4N1"  - N#O	N:O
N1ON7O