Subject: Re: [xsl] Merging lines of 3 words or less From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 8 Sep 2005 11:53:12 +0100 |
> Then inside the recreated line for each of the current group (which is > what at this point?) current-group() return the sequence of items (that is things selcted by the xsl:for-each-group select="l") that are um in the current group (which in this case means a group of adjacent line with just the first one having a 4th word. position() positions the groups (rather than teh items as it would in a xsl:for-each) so <l n="{position()}"> does the right thing, then to get the content of the lines <xsl:copy-of select="current-group()"/> would actually give you back each of the l elements in the group, which you don't want, you just want the contents of each of those lines so <xsl:copy-of select="current-group()/node()"/> would almost work but I wasn't sure if you needed to put a space at the point that you joined the lines back so I did <xsl:for-each select="current-group()"> <xsl:copy-of select="(node(),' ')"/> </xsl:for-each> which for each of the original lines copies all the children then adds a space that puts a space at the end as well so perhaps <xsl:for-each select="current-group()[position()!=last()]"> <xsl:copy-of select="(node(),' ')"/> </xsl:for-each> <xsl:copy-of select="current-group()[position()=last()]/node()"/> or something. If you know that <lg n="44.6"><l n="3" and > <lg n="100.8"><l n="4"> really are short lines, then you can change things to <xsl:for-each-group select="l" group-starting-with=" l[w[4]] | lg[@n='44.6']/l[@n='3'] | lg[@n='100.8']/l[@n='4'] "> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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