Re: [xsl] can't get xsl:sort to work

[UlyLee <ulyleeka@xxxxxxxxx>]

Thanks guys! this mailing list is really great for
newibes like me... again thanks a lot! (i never
thought the solution would be that simple... hehehe!)

UlyLee

--- Joris Gillis <roac@xxxxxxxxxx> wrote:

> Tempore 12:58:08, die 09/19/2005 AD, hinc in
> xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit UlyLee
> <ulyleeka@xxxxxxxxx>:
> 
> > <xsl:for-each select="//complexarticle |
> > //simplearticle | //dummyarticle">
> > <xsl:sort select="@entry">
> > <tr valign="top">
> > <td><xsl:value-of select="@id"/></td>
> > <td><xsl:value-of select="@entry"/></td>
> > <td><xsl:variable name="x"
> select="count(.//xref)"/>
> > <xsl:for-each select=".//xref">
> > <xsl:value-of select="."/>
> > <xsl:if test="position() &lt; $x">
> > <br/>
> > </xsl:if>
> > </xsl:for-each>
> > </td>
> > </tr>
> > </xsl:sort>
> > </xsl:for-each>
> >
> > but when i run the transformation (i'm using
> > xmlspy) i get and error "Expected select attribute
> or
> > non empty content not both" but i have a select
> > attribute.
> 
> The error message says it all.
> You need:
> <xsl:sort select="@entry"/>
> you don't have to encapsulate the whole loop with
> this element;-)
> 
> regards,
> -- 
> Joris Gillis
> (http://users.telenet.be/root-jg/me.html)
> Gaudiam omnibus traderat W3C, nec vana fides
> 
> 



		
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