Subject: Re: [xsl] Adding elements to unknown tree structure From: Gustave Stresen-Reuter <tedmasterweb@xxxxxxx> Date: Tue, 27 Sep 2005 23:01:26 +0100 |
Ted Stresen-Reuter http://www.tedmasterweb.com
This looks like a grouping problem to me. You may use Muenchian grouping to solve this as shown below.
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes" />
<xsl:key name="by-folder-name" match="folder" use="@name" />
<xsl:template match="/root"> <root> <xsl:for-each select="folder[generate-id() = generate-id(key('by-folder-name', @name)[1])]"> <folder name="{@name}"> <xsl:copy-of select="key('by-folder-name', @name)/*" /> </folder> </xsl:for-each> </root> </xsl:template>
</xsl:stylesheet>
The XML file is <root> <folder name="documents"> <folder name="personal" /> </folder> <folder name="documents"> <folder name="public" /> </folder> </root>
The output produced is <?xml version="1.0" encoding="UTF-8"?> <root> <folder name="documents"> <folder name="personal"/> <folder name="public"/> </folder> </root>
This solution is not generic. But the concept might help.
Regards, Mukul
On 9/25/05, Gustave Stresen-Reuter <tedmasterweb@xxxxxxx> wrote:Thanks for the pointers. I'm getting there, but have an interim question.
Given
<folder name="documents"> <folder name="personal" /> <folder/> <folder name="documents"> <folder name="public"> </folder>
How do I get:
<folder name="documents"> <folder name="personal" /> <folder name="public"> </folder>
The few places I've looked indicate that I should use something like this:
<xsl:copy-of select="not(@name = following::*/@name)" />
but that isn't working. Other things I've tried return the whole document. Also, I'm afraid that this solution would not return the name="public" child element of the second folder element.
Basically, I'm looking for a "merged" version of these two fragments. By "merged" I mean that if an element has the same ancestors, the same attributes, and the attribute have the same values, but the node content is different, the content should be added to the same node appearing earlier in the document.
Any ideas?
Ted Stresen-Reuter
On Sep 21, 2005, at 9:06 PM, Joris Gillis wrote:
Hi,
Tempore 17:41:53, die 09/21/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Gustave Stresen-Reuter <tedmasterweb@xxxxxxx>:
Given:
<myxmlfile> <folder name="root"> <folder name="documents"> <document name="passwords"> 123456 </document> </folder> <folder name="pictures"> <folder name="family" /> </folder> </folder> </myxmlfile>
parameter: folder_name = "friends" parameter: path2folder = root/pictures
How can I create a new folder element named "friends" in the pictures
element?
Keep in mind that I need to make sure that both "root" and "pictures"
exist and if they don't, create them first.
See if you can get this stylesheet working: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/>
<xsl:template match="/"> <xsl:apply-templates> <xsl:with-param name="path2folder">/root/pictures/friends</xsl:with-param> </xsl:apply-templates> </xsl:template>
<xsl:template match="node()">
<xsl:param name="path2folder"/>
<xsl:param name="good" select="true()"/>
<xsl:variable name="path" select="substring-before($path2folder,'/')"/>
<xsl:variable name="verygood"
select="($good and @name=$path) or self::myxmlfile"/>
<xsl:variable name="pathafter"
select="substring-after($path2folder,'/')"/>
<xsl:variable name="nextpath"
select="substring-before($pathafter,'/')"/>
<xsl:variable name="folder" select="folder[@name=$nextpath][$good]"/>
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="node()">
<xsl:with-param name="path2folder" select="$pathafter"/>
<xsl:with-param name="good" select="$verygood"/>
</xsl:apply-templates>
<xsl:if test="$verygood and not($folder) and not($path2folder='')">
<xsl:call-template name="createFolder">
<xsl:with-param name="path2folder" select="$pathafter"/>
</xsl:call-template>
</xsl:if>
</xsl:copy>
</xsl:template>
<xsl:template name="createFolder">
<xsl:param name="path2folder"/>
<folder name="{substring-before(concat($path2folder,'/'),'/')}">
<xsl:if test="contains($path2folder,'/')">
<xsl:call-template name="createFolder">
<xsl:with-param name="path2folder"
select="substring-after($path2folder,'/')"/>
</xsl:call-template>
</xsl:if>
<xsl:if test="not(contains($path2folder,'/'))">
<xsl:comment>folder inserted</xsl:comment>
</xsl:if>
</folder>
</xsl:template>
</xsl:stylesheet>
regards, -- Joris Gillis (http://users.telenet.be/root-jg/me.html) Don't send spam. I don't like it and it is illegal.
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