Subject: Re: [xsl] XSLT recursion problem From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> Date: Wed, 28 Sep 2005 10:29:30 +0200 |
> The real problem is that I don't want to have to know anything about > <sometag>. That is, I would be free to use (and nest!) whatever > non-proprietary tag inside my <repeat>, without modifing it. > Probably there's no way in XSLT 1.0 (if it is, why creating tunnel in > 2.0 ;) , but if you see another solution... > Hi again Paolo, Why can you not have a general template for the "Sometag" and other elements that you just want to pass on? I think that your own solution would be able to provide, if you change the template that matches "Sometag" to the following: <xsl:template match="*"> <xsl:param name="index" select="1"/> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates> <xsl:with-param name="index" select="$index"/> </xsl:apply-templates> <!-- sometag content --> </xsl:copy> </xsl:template> The match="ax:items" is more specific than match="*" and thus has higher priority. My solution, I think, you would have to change three templates: <xsl:template match="ax:repeat"> <xsl:apply-templates/> <!-- instead of <xsl:apply-templates select="sometag"/>--> </xsl:template> <xsl:template match="*"> <!-- Instead of <xsl:template match="sometag" --> <xsl:copy> <!-- Copy element (shallow copy) --> <xsl:copy-of select="@*"/> <!-- Copy all attributes --> <!-- other non-proprietary elements to be processed: --> <xsl:apply-templates select="*[not(self::ax:items)]"/> <!-- Propriotary elements to be processed: --> <xsl:apply-templates select="ax:items[1]" mode="first"/> </xsl:copy> </xsl:template> And remove the <sometag> and </sometag>from the <xsl:template match="ax:items" mode="first"> .. </ Is this what you need? Regards, Ragulf Pickaxe :-)
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