[xsl] Complicated transformation step when using localization

[knocte <knocte@xxxxxxxxx>]

Hello list!
I am trying to make a transformation step but I can't get it to work!

I will receive an XML document with many nodes. Some of them may contain 
the attribute "translate-attrs":

<...>
<img src="myURI" alt="translate me" title="me too" translate-attrs="alt 
title" />
<...>

I want to select all the nodes that have this attribute and replace the 
content of the attributes with the content of an external file, like this:

<external-dictionary>
 <text key="translate me">Translate me, in other language</text>
 <text key="me too">Me too, in other idiom</text>
</external-dictionary>

Expected final XML result would be:

<...>
<img src="myURI" alt="Translate me, in other language" title="Me too, in 
other idiom" />
<...>


So first we want to match all the nodes that have this attribute:

<xsl:template match="*[@translate-attrs]">


Then we want to copy all attributes except the one mentioned:

 <xsl:copy-of select="@*[not (local-name()='translate-attrs')]" />

Now I want to do a for-each part which captures all of the terms 
separated by spaces that are contained in the translate-attrs attribute, 
and make an attribute by each, with the content of the external XML 
file, but I can't achieve it! It would be something like:

 <xsl:for-each select"@translate-attrs">
   <xsl:attribute name=".">
     <xsl:value-of 
select="document($myxml)//external-dictionary/text[@key = 
current()/@{.}]" />
   </xsl:attribute>
 </xsl:for-each>

Finally, we need to copy the rest of the child elements:

 <xsl:apply-templates />
</xsl:template>


Does anybody know how can I make the middle part, the most difficult 
one? Any help will be appreciated!

   Regards,

       Andrew    [ knocte ]

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