Re: [xsl] matching on several elements, but determine which was matched

["Roger Chi" <roger.xslt@xxxxxxxxxxxx>]

You could do something like:

<xsl:template match="h1|h2|h3|h4|h5|h6">
  <xsl:element name={concat('title',substring(name(),2,1))}">
    <xsl:text>HTML Heading</xsl:text>
  </xsl:element>
</xsl:template>

On 10/20/2005, "Dominik Zayer" <dzayer@xxxxxxxxxxxxxx> wrote:

>Hi
>
>I have some very similar XML elements (html headings) which produce very
>similar XSLT output. Know i'm wondering if i could use some wildcards to
>tauten my code.
>
>Here's a part of the XSLT to get you an idea what i am talking about:
><xsl:template match="h1">
>        <title1>HTML Heading</title1>
></xsl:template>
><xsl:template match="h2">
>        <title2>HTML Heading</title2>
></xsl:template>
>....and so on till <h6>...
>
>Is it possible to do something like:
><xsl:template match="h1|h2|h3|h4|h5|h6">
>	#determine which element was matched and write the according output
>element#
></xsl:template>
>
>the matching seems to work this way, but i don't have a clue how to
>output the correct tag...
>
>Thanks for help, hints or a kick in the ass (if this question is really
>stupid) ;)
>
>Best,
>Dominik
>
>
>
>--
>Dominik Zayer  > Development
>iconmobile GmbH > Methfesselstr. 32-36 > D-10965 Berlin
>phone +49 30 789 519 13 > fax +49 30 890 686 50
>dzayer@xxxxxxxxxxxxxx > http://www.iconmobile.com