Subject: Re: [xsl] foreach, preceding-sibling::node() and following-sibling::node() From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 27 Oct 2005 11:32:27 +0100 |
You have <xsl:choose> <xsl:when test="idlink"> <xsl:copy-of select="idlink[1]/preceding-sibling::node()"/> <xsl:for-each select="idlink"> That says, if the curent node has an idlink child anywhere, first copy all the children after the first idlink (including any later idlinks) then after that process all the idlink elements. You don't want to do that at all, you just want to process each element in the order it appears in the file, so replace all of the code you showed by a single <xsl:apply-templates/> then have a template for idlink that makes a link,as has been shown earlier. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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