Subject: [xsl] how to convert from list to grid ? From: "Bru, Pierre" <Pierre.Bru@xxxxxxxxxxxx> Date: Sun, 30 Oct 2005 23:48:04 +0100 |
hello, I've been racking my brains for a couple of weeks now but I can not find a way to do the folowing: I have a list reprenting the type and integer coordinate of various items on a square grid like this one: <list> <item id="1" type="foo" x="1" y="7" /> <item id="2" type="bar" x="8" y="2" /> <item id="3" type="foo" x="8" y="2" /> <item id="4" type="bar" x="8" y="3" /> <item id="5" type="bar" x="8" y="3" /> <item id="6" type="bar" x="8" y="3" /> ... </list> - "id" are unique - each cell may contain any number of item (including 0). - there are as many lines as needed for each cell (see [8,2] or [8,3]) - the cell are in no particular order for now but this can be changed as needed I would like to transform this list into a square grid (table?) with : - if the cell contains no item, an empry cell - otherwise, the count of item(s) of each type (one value for each type present on the cell) is this feasable with XSLT ? TIA, Pierre.
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