Subject: Re: [xsl] How to process a list of files From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> Date: Tue, 8 Nov 2005 13:11:55 +0100 |
Hi, I am not quite sure what you mean. I do not know the processor used in the example, but from what you ask, and from the example shown, it would seem that you would be able to use href="{$filename}" where $filename is the full name of the output document that you want. Other processors may have different syntax. Ragulf Pickaxe :-)
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