Re: [xsl] How to process a list of files

Subject: Re: [xsl] How to process a list of files
From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx>
Date: Tue, 8 Nov 2005 13:11:55 +0100
Hi,

I am not quite sure what you mean.
I do not know the processor used in the example, but from what you
ask, and from the example shown, it would seem that you would be able
to use href="{$filename}" where $filename is the full name of the
output document that you want.

Other processors may have different syntax.

Ragulf Pickaxe :-)

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