Subject: RE: [xsl] Node ordering question with preceding axis From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sun, 27 Nov 2005 09:15:20 -0000 |
The result of a path expression (an expression involving "/") is always in document order. I'm not sure exactly what you want, but you might be able to get it by replacing A/B with for $a in A return $a/B which doesn't sort into document order. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Kenneth Stephen [mailto:marvin.the.cynical.robot@xxxxxxxxx] > Sent: 27 November 2005 01:43 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Node ordering question with preceding axis > > Hi, > > I have the following testcase: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="2.0"> > > <xsl:output method="xml" omit-xml-declaration="yes" /> > > <xsl:variable name="forest"> > <tree>One</tree> > <tree>Two</tree> > <tree><tree>Three</tree></tree> > <tree><tree>Four</tree><tree>Five</tree></tree> > > <tree><tree>Six</tree><tree>Seven</tree><tree>Eight</tree></tree> > </xsl:variable> > > <xsl:template match="/"> > > <xsl:value-of select="$forest//tree[text() = > 'Eight']/preceding::*" /> > </xsl:template> > > </xsl:stylesheet> > > When run, this code produces: > > One Two Three Three FourFive Four Five Six Seven > > I'm not entirely clear about the expected behaviour of preceding > axis with temporary trees, but I was expecting that the for the last > "forest" of nodes, the node ordering would be "Seven" followed by > "Six" since preceding is a reverse axis. What am I missing? > > Thanks, > Kenneth
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