Re: [xsl] replace a word

[Kamal Bhatt <kbhatt@xxxxxxxxx>]

This is correct. sub is not an element, it will therefore only find and 
replace once.

What you need is a recursive call that will keep recursing till there 
are no more instances of {sub}.

There are a number of examples of similar situations on the mailing list.

Cheers.

Kamal.

T Uma Shankari wrote:

> Greetings to all,
>
>   I have to find a word and replace that word with another word.
>
> for example if my xml file is like this means
>
> <question page="6" Queswav="" ChooseType="" id="0" Qno="533" 
> chapter="chapter1" >
>   <stmt1 mgif1="" mgif="" Qno="533" misc="" >statement1</stmt1>
>   <opt ptno="1" mgif1="" mgif="" " misc=""
>
> > {sub}2{/sub}Option1{sub}5{/sub}</opt>
>
>   <opt ptno="1" mgif1="" mgif="" " misc="" >Option2</opt>
>   <opt ptno="1" mgif1="" mgif="" " misc="" >Option3</opt>
>   <opt ptno="1" mgif1="" mgif="" " misc="" >Option4</opt>
>  </question>
>
>
> i need to find the {sub} and replace it with {/sub} so i have written 
> this code.
>
> xsl:template match="question" name="main">
>  <xsl:for-each select="self::question">
>            <xsl:variable name="stringques1">
>               <h1><b><xsl:value-of select="opt" /></b></h1>
>             </xsl:variable>
>
> <xsl:variable name="stringques2">
>  <xsl:choose>
>  <xsl:when test="(contains($stringques1,'{sub}'))">
>  <xsl:value-of select="substring-before($stringques1,'{sub}')"/>
>    <sub>
>    <xsl:value-of 
> select="substring-before(substring-after($stringques1,'{sub}'),'{/sub}')"/> 
>
>    </sub>
>   <xsl:value-of select="substring-after($stringques1,'{/sup}')" />
>       </xsl:when>
>        <xsl:otherwise>
>         <xsl:value-of select="$stringques1"/>
>       </xsl:otherwise>
>      </xsl:choose>
>     </xsl:variable>
>  </xsl:for-each>
>   </xsl:template>
>  </xsl:stylesheet>
>
>
>  It is replacing the first occurance not the oncoming occurance. Can 
> anyone please tell where i am wrong?
>
> regards
> uma