Re: [xsl] counting in for each

[Andrew Franz <afranz0@xxxxxxxxxxxxxxxx>]

A useful technique...

1. In your CSS file, define odd & even rows as follows:
.row0  { color: #FFFFFF; }
.row1  { color: #FFD0FF; }

2. In your XSL stylesheet:

<xsl:for-each select="item">
	<tr class="row{(position() mod 2)}">...</tr>
</xsl:for-each>




Michael Kay wrote:

> The usual way to handle such requirements is with code such as this:
>
> <xsl:for-each select="item">
>  <xsl:choose>
>    <xsl:when test="position() mod 2 = 0">...</xsl:when>
>    <xsl:otherwise>...</xsl:otherwise>
>  </xsl:choose>
> </xsl:for-each>
>
> Withing the for-each, the total number of items is available as the result
> of the function last().
>
> Michael Kay
> http://www.saxonica.com/ 
>
>  
>
> > -----Original Message-----
> > From: Dietmar Klotz [mailto:dklotz@xxxxxxxxxxx] 
> > Sent: 09 December 2005 20:12
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] counting in for each
> >
> >
> > I am making a list with "for each" and if the list is 1 or 3 
> > items it should
> > change the state of display. And I would also like to change the Icon
> > depending on how many objects there are....so object 1 has 
> > icon 1...object 2
> > icon 2
> >
> > So my question. Is it possible to count how many Items there 
> > are in a node?
> > And do I know where I am in a for each?
> >
> > Thanks to all!
> >
> > Dietmar Klotz