Subject: RE: [xsl] Selecting the first item from a tokenized string From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 13 Jan 2006 14:22:50 -0000 |
> Michael Kay wrote: > > > you can get the Nth item in a sequence using SEQ[N]. > > In the rare cases where that's inconvenient because > > it changes the evaluation context, you can use > > subsequence(SEQ, N, 1). > > When can this happen? Can you show an example? > > Regards, > > --drkm > Suppose that you have a structure like this: <e> <itemref nr="5"/> <itemref nr="7"/> <itemref nr="10"/> </e> <f> <item/>... </f> and you want to select the 5th, 7th, and 10th <item> elements. You can't do <xsl:for-each select="/e/itemref"> <xsl:value-of select="/f/item[@nr]"/> because the context inside the predicate is wrong. But you can do <xsl:for-each select="/e/itemref"> <xsl:value-of select="subsequence(/f/item, @nr, 1)"/> Of course there are other circumventions as well, involving variables or current() - but it's nice to be aware of this alternative. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Florent Georges [mailto:darkman_spam@xxxxxxxx] > Sent: 13 January 2006 13:14 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] Selecting the first item from a tokenized string > > > > > > > > > > > > > > > > > > > > > > > > ______________________________________________________________ > _____________ > Nouveau : tiliphonez moins cher avec Yahoo! Messenger ! > Dicouvez les tarifs exceptionnels pour appeler la France et > l'international. > Tilichargez sur http://fr.messenger.yahoo.com
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