Re: [xsl] Display unique values?

George, 

Excellent! That is certainly much cleaner than my
original, and it works, which is always a plus. Thanks
very much!

- Alan

--- George Cristian Bina <george@xxxxxxxxxxxxx> wrote:

> Hi Alan,
> 
> Your stylesheet looks complicated, how about:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>    <xsl:output version="1.0" encoding="UTF-8"
> indent="no" 
> omit-xml-declaration="no"
>      media-type="text/html"/>
> 
>    <xsl:template match="/">
>      <html><table>
>        <thead><tr>
>          <td>Event</td><td>Device</td>
>        </tr></thead>
>        <tbody>
>          <xsl:apply-templates/>
>        </tbody>
>      </table></html>
>    </xsl:template>
> 
>    <xsl:template match="Event">
>      <tr>
>        <td><xsl:value-of select="ID"/></td>
>        <td>
>          <xsl:for-each 
>
select="EventDevicesArchive/EventDevice/Device[not(text()=../preceding-sibling::EventDevice/Device/text())]">
>              <xsl:value-of select="."/>
>              <xsl:if test="position()!=last()">
>                <xsl:text>, </xsl:text>
>              </xsl:if>
>          </xsl:for-each>
>        </td>
>      </tr>
>    </xsl:template>
> </xsl:stylesheet>
> 
> Hope that helps,
> George
>
---------------------------------------------------------------------
> George Cristian Bina
> <oXygen/> XML Editor, Schema Editor and XSLT
> Editor/Debugger
> http://www.oxygenxml.com
> 

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