Subject: Re: [xsl] Selecting attribute from previous parent node From: Florent Georges <darkman_spam@xxxxxxxx> Date: Sat, 28 Jan 2006 17:26:17 +0100 (CET) |
Jay Bryant wrote: > >ancestor::flower[@type!='tulip'] > The trouble with that is that it selects every flower node > whose type attribute does not contain 'tulip on the entire > axis. If there's more than one non-tulip flower node up > the ancestor axis, this expression will get all of them, > which will either generate errors or lead to unexpected > results. It needs the position predicate ([1]) to get the > first ancestor node (which is the most immediate node on > the axis). > So, it needs to be > ancestor::flower[1]/@type If I understand right the requirment, you mean: ancestor::flower[@type!='tulip'][1] dont'you? --drkm ___________________________________________________________________________ Nouveau : tiliphonez moins cher avec Yahoo! Messenger ! Dicouvez les tarifs exceptionnels pour appeler la France et l'international. Tilichargez sur http://fr.messenger.yahoo.com
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