Re: [xsl] Including <?xml ...> in the result tree

Subject: Re: [xsl] Including <?xml ...> in the result tree
From: Emmanouil Batsis <Emmanouil.Batsis@xxxxxxxxxxx>
Date: Mon, 30 Jan 2006 11:49:35 +0200
taka a look at the xsl:output element.

Sebastian Tennant wrote:

Hi all,

I want to output an XHTML doc with the following prologue:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>


However an xsl template including the following:

 <xsl:processing-instruction name="xml">
   version="1.0" encoding="UTF-8"
 </xsl:processing-instruction>
 <![CDATA[
   <?xml version="1.0" encoding="UTF-8"?>
   <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
                "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>]]>

produces the following error in xalan:

XSLT Error: A processing instruction name cannot be 'xml'

and the cdata section is output as &lt;!DOCTYPE... etc.

How best should this be achieved?

TIA

sdt

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