Subject: Re: [xsl] Printing all child bachelor nodes From: Douglas F Shearer <dougal.s@xxxxxxxxx> Date: Thu, 9 Feb 2006 15:52:06 +0000 |
Douglas F Shearer dougal.s@xxxxxxxxx http://douglasfshearer.dyndns.org
On 2/9/06, Douglas F Shearer <dougal.s@xxxxxxxxx> wrote:Hi there.
I have the following snippet of XML and would like to extract the data given below using XSL...
********** XML ************
<features>
<pool length="30" max-depth="160" min-depth="30" indoor="false"/>
<DVD/>
<beds twin="2" sofa-bed="1"/>
</features>
******** REQUIRED OUTPUT ****** pool: length: 30, max-depth:160, min-depth:30, indoor: false. DVD. beds: twin:2, sofa-bed:1
**************************************
The main issue I am having is that the nodes themselves change (microwave instead of DVD etc). Basically I want to print out all of the elements within the features element, and their associated attributes.
<xsl:template match="features/*"> <xsl:value-of select="local-name()"/> <xsl:for-each select="@*"> <xsl:value-of select="concat(' ', name(), ':', .)"/> <xsl:if test="position() != last()">,</xsl:if> </xsl:for-each> <xsl:text>.</xsl:text> </xsl:template>
Did you really want text output? If so you will need to add CRs in there, but I'm guess you'll be using HTML. Also, beds didn't end with a . which I'm also assuming was a typo.
cheers andrew
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