RE: [xsl] help with select

["Michael Kay" <mike@xxxxxxxxxxxx>]

I haven't studied the question closely but you probably want 

footnote[@id=current()/@fnref]

Note that ./@fnref means the same as @fnref, so

footnote[@id=./@fnref]

looks for a footnote whose id and fnref attributes have the same value.

Following cross-references is often best done using keys: it's certainly
more efficient and many people say the code is clearer. Look up xsl:key.

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: Jiang, Peiyun [mailto:Peiyun.Jiang@xxxxxxxxxxxxxx] 
> Sent: 09 February 2006 16:20
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] help with select
> 
> I'm trying to made the following code work: 
> ./footnote|//footnote[@id=./@fnref]
> 
> I want to select the child footnote element of author and any 
> footnote that its id attribute matches the fnref attribute of 
> the author.
>  
> In footnote[@id=./@fnref], is "." referring to author or to 
> footnote? How do you refer author?
> 
> Thanks.
> 
> Peiyun
> 
> 
> <xsl:template match="author">
>     <!-- something here -->
> 	     <xsl:choose>
> 	     <xsl:when 
> test="count(./footnote|//footnote[@id=./@fnref]) = 1">
> 	        <xsl:apply-templates 
> select="./footnote|//footnote[@id=./@fnref]"/>
> 	     </xsl:when>
> 	 
> 	     <xsl:when 
> test="count(./footnote|//footnote[@id=./@fnref]) &gt; 1">
> 	        <xsl:for-each 
> select="./footnote|//footnote[@id=./@fnref]">
> 	            <xsl:choose>
> 	               <xsl:when test="position() = last()">
> 	                  <xsl:apply-templates select="." /> 
> 	               </xsl:when>
> 	               <xsl:when test="position() != last()">
> 	                  <xsl:apply-templates select="." />
> 	                  <sup>,<xsl:text>&#x20;</xsl:text></sup>
> 	               </xsl:when>	                
> 	            </xsl:choose>
> 	        </xsl:for-each>
> 	     </xsl:when>	     
> 	     </xsl:choose>
> 
>   <!-- some other things here -->
> </xsl:template>