Subject: Re: [xsl] Returning an element's position number From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 16 Feb 2006 15:21:08 GMT |
see the recent thread (with the rather unhelpful tile "Re: [xsl] Stumped on XPath") The trick with doing cross references in XSLT is always generate the reference text _at the referenced node_ not on the referencing node. then you can easily get the same number in the reference and in the referenced heading. (Often by just calling a named template or special mode that just does the numbering. so just have <xsl:key name="l" match="legend" use="@id"/> then on your reference element do <xsl:for-each select="key('l',@link)"> <xsl:number/> </xsl:for-each< so that you generate the number on the <legend element even though it is output at the point of the reference. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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