Subject: Re: [xsl] constructing a "variable" select argument From: Florent Georges <darkman_spam@xxxxxxxx> Date: Mon, 27 Feb 2006 20:29:55 +0100 (CET) |
Tracey Zellmann wrote: > However, this does not: > after calling the template with > <xsl:with-param name="track" select="T1"/> You're selecting here element nodes that are childs of the context node and whose name is 'T1'. But I wonder if you don't want the string 'T1' instead: <xsl:with-param name="track" select="'T1'"/> (note the additional quotes). Regards, --drkm ___________________________________________________________________________ Nouveau : tiliphonez moins cher avec Yahoo! Messenger ! Dicouvez les tarifs exceptionnels pour appeler la France et l'international. Tilichargez sur http://fr.messenger.yahoo.com
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