Subject: RE: [xsl] xmlns print and enumerate From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Thu, 9 Mar 2006 19:15:19 -0000 |
In XSLT 2.0 you use <xsl:namespace name="{@prefix}" select="@uri"/> In XSLT 1.0 there's a circumlocution something like: <xsl:variable name="temp"> <xsl:element name="{@prefix}.dummy" namespace="{@uri}"/> </xsl:variable> <ns> <xsl:copy-of select="xx:node-set($temp)//namespace::*"/> </ns> but even this needs the node-set() extension; I don't think there's a pure XSLT 1.0 solution. It also relies on an erratum to the original XSLT 1.0 spec concerning copying of namespace nodes. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Michele Vivoda [mailto:idmichele@xxxxxxxx] > Sent: 09 March 2006 19:04 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] xmlns print and enumerate > > Thank you very much, exactly what I was looking for, > I was missing the namespace operator. > > For my mistake, I made a "wrong" question (the number > 1), > what I would like to know additionally is, > how do I transform the final result of question 2: > > <b> > <ns prefix='h' uri='http://foo'/> > </b> > > "back" to the source: > > <a xmlns:h='http://foo'/> > > I am dealing with qnames in attribute values... > (lower case to distinguish them from QNames of node > names ;-) > > Thanks again, > Michele Vivoda > > > > > > > ___________________________________ > Yahoo! Mail: gratis 1GB per i messaggi e allegati da 10MB > http://mail.yahoo.it
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