Subject: [xsl] Using a variable as the xml node - ignore my previous mail From: bharathi kongara <bharathikongara@xxxxxxxxx> Date: Fri, 24 Mar 2006 06:58:02 -0800 (PST) |
Hi everyone, I've been playing with this problem from yesterday, tried all sort of solutions, but no use. Here is the problem: In my xsl, I'm referring to a configuration file which is an xml file. 1000ConfigFile.xml: <ConfigFile> <100Code>Hundred<100Code> <200Code>Twohundred</200Code> . . . </ConfigFile> and the xsl file is: key1 refers to the 1000 in the name of the config file. key2 refers to the 100 or 200 ... in the nodes in the config file. They will come from a stored procedue. <xsl:variable name="Config" select="document(concat(//key1,'Config.xml'))"/> Now my problem is, I've to refer to the 100 node or 200 node etc which depends on the key2. I'm doing this - define a vraible for refrerring to the node based on key2. <xsl:variable name="loc" select="concat('$Config/ConfigFile/',//key2,'Code')" /> When I'm referring to the "loc" variable in the xsl later as $loc, it is putting in the string "$Config/ConfigFile/100Code" instead of substituting the value "Hundred" from that node. But it works when I directly use the $Config/ConfigFile/100Code instead of $loc. Any ideas? Any help is greatly appreciated. Thanks in Advance, Bharathi __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
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