Subject: RE: [xsl] Determining the context node From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 13 Apr 2006 11:29:09 -0400 |
You can get the name of the context node using name(). Saxon has an extension function saxon:path() which gives you a full path to a node; I believe there are portable solutions to this problem at
http://www.dpawson.co.uk/xsl/sect2/N6077.html
but it seems to be down.
<xsl:template match="*" mode="make-path"> <xsl:apply-templates select="ancestor-or-self::*" mode="make-step"/> </xsl:template>
<xsl:template match="*" mode="make-step"> <xsl:text>/</xsl:text> <xsl:value-of select="name()"/> <xsl:if test="(preceding-sibling::*|following-sibling::*) [name()=name(current())]"> <xsl:text>[</xsl:text> <xsl:number/> <xsl:text>]</xsl:text> </xsl:if> </xsl:template>
Cheers, Wendell
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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