Re: [xsl] sum up float values problem

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

Exactly as explained by Dr. Kay:

   sum(/*/*/xs:double(translate(.,',','.')))



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Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.



On 4/27/06, Markus Gamperl <markus.gamperl@xxxxxx> wrote:
> Dear experts!
>
> XSL 1.0:
> I have got the following XML:
>
> <POSITION>
>  <LSUM>14,68</LSUM>
>  <LSUM>321</LSUM>
>  <LSUM>13</LSUM>
>  <LSUM>100,6</LSUM>
> ...
> </POSITION>
>
> I want to sum up all my LSUM elements. When I do a sum(//LSUM) I only get a
> number value, not a float value... This would work if the float values are
> separated with a '.' not a ',' (eg. 14.68). But I get the values separated
> with a ','...
>
> So I had following idea:
> sum(translate(//LSUM,',','.'))
>
> But the translate function only returns the first node (14.68) of the
> nodeset...
>
> Do you have an idea how to solve this issue simply?
>
> Thanks
> Markus
>
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