Subject: Re: [xsl] Sort an xml file by the using the ordering/sorting information from another xml file From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Thu, 11 May 2006 14:06:18 +0530 |
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:variable name="doc" select="/" /> <xsl:variable name="sortorder" select="document('SortingOrder.xml')" />
<xsl:template match="/myRoot"> <myRoot> <xsl:for-each select="$sortorder/mySortingOrder/myElement"> <xsl:copy-of select="$doc/myRoot/myElement[@key = current()/@key]" /> </xsl:for-each> </myRoot> </xsl:template>
Regards, Mukul
sortin=I want to sort the elements of an xml file, The criteria of ordering is actually specified in another xml file.
Can i use xsl to sort one xml file by the using the ordering data from another xml file?:
I give a small e.g.
The Original xml file: main.xml
<myRoot> <myElement key=3D"Tokyo" country=3D"JAP">I am Tokyo</myElement> <myElement key=3D"NewYork" country=3D"US">I am NewYork</myElement> <myElement key=3D"Sydney" country=3D"AUS">I am Sydney</myElement> <myElement key=3D"London" country=3D"UK">I am London</myElement> </myRoot>
The Sorting Criteria xml file: SortingOrder.xml: <mySortingOrder> <myElement key=3D"NewYork" /> <myElement key=3D"London" /> <myElement key=3D"Tokyo" /> <myElement key=3D"Sydney" /> </mySortingOrder>
After sorting the final xml data i should get is: <myRoot> <myElement key=3D"NewYork" country=3D"US">I am NewYork</myElement> <myElement key=3D"London" country=3D"UK">I am London</myElement> <myElement key=3D"Tokyo" country=3D"JAP">I am Tokyo</myElement> <myElement key=3D"Sydney" country=3D"AUS">I am Sydney</myElement> </myRoot>
in the final xml, the myElement elements are sorted according to the
g order specified in SortingOrder.xml.
Can i achieve this using xsl? Normally for the xsl:sort the sorting information should be present in the element itself.
Thanks in advance. Jagdishwar.
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