Subject: Re: [xsl] Removing duplicates after list is sorted From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 11 May 2006 12:57:17 -0400 |
Cheers, Wendell
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
If your creation dates were in a form that could be compared as numbers you could just do this:
<xsl:output indent="yes"/>
<xsl:key name="base" match="Document" use="Report/@base"/>
<xsl:template match="docs">
<docs>
<xsl:for-each select="Document[generate-id()=generate-id(key('base',Report/@base))]">
<xsl:variable name="thisgrp" select="key('base',Report/@base)"/>
<xsl:copy-of select="$thisgrp[not(@CREATIONTIME > $thisgrp/@CREATIONTIME)][1] "/>
</xsl:for-each>
</docs>
</xsl:template>
</xsl:stylesheet>
but since they are not, I think something like this is what you want
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:key name="base" match="Document" use="Report/@base"/>
<xsl:template match="docs">
<docs>
<xsl:for-each select="Document[generate-id()=generate-id(key('base',Report/@base))]">
<xsl:for-each select="key('base',Report/@base)"> <xsl:sort select="@CREATIONTIME"/> <xsl:if test="position()=last()"> <xsl:copy-of select="."/> </xsl:if> </xsl:for-each> </xsl:for-each> </docs> </xsl:template>
</xsl:stylesheet>
$ saxon dup.xml dup.xsl <?xml version="1.0" encoding="utf-8"?> <docs> <Document CREATIONTIME="200605051507">
<Report ID="759d" base="ELS">
<Authorized ASC="2"/>
</Report>
</Document> <Document CREATIONTIME="200605041506">
<Report ID="759c" base="LAN">
<Authorized ASC="0"/>
</Report>
</Document> </docs>
David
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