Subject: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic From: cknell@xxxxxxxxxx Date: Wed, 17 May 2006 17:29:37 -0400 |
Given a parameter, let's call it "today" in the form of this string "20060517", how do I create a variable, let's call it "tMinus1" such that it represents a day earlier than "20060517", that would be "20060516". So long as "$today" isn't the first day of a month, a simple subtraction and followed by a type cast that I don't grasp would do the trick. What I'm looking for is guidance on date arithmetic. Thanks. -- Charles Knell cknell@xxxxxxxxxx - email
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] transforming from xml to , George Cristian Bina | Thread | RE: [xsl] XSLT 2.0/XPath 2.0 Date a, Karen McAdams |
RE: [xsl] Collect word count with x, Karen McAdams | Date | RE: [xsl] XSLT 2.0/XPath 2.0 Date a, Karen McAdams |
Month |