Subject: Re: [xsl] Sorting an xml From: "Jagdishwar B" <jagdishwar.beemanati@xxxxxxxxx> Date: Mon, 22 May 2006 17:18:56 +0200 |
----------------------------------------------------------
The printout for this should be sorted by <place> like this: Kyl och frys: Lax 8 st Grddde 1,2 l
Frukt och grvnt: Chalottenlvk 4 st
Vvrigt: Matlagningsvin 0,66 l
It would be easier to understand if you give what output xml you are looking for.
you can try: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!-- default identity translation --> <xsl:template match="*|@*|comment()|processing-instruction()|text()"> <xsl:copy> <xsl:apply-templates select="*|@*|comment()|processing-instruction()|text()"/> </xsl:copy> </xsl:template> <!-- start processing with the root element --> <xsl:template match="shopinglist"> <xsl:copy> <xsl:apply-templates select="item"> <xsl:sort select="place"/> </xsl:apply-templates> </xsl:copy> </xsl:template> </xsl:stylesheet>
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Sorting an xml, Jon Gorman | Thread | Re: [xsl] Sorting an xml, Jimmy Åhs |
[xsl] xml:output indent="yes" wins , David Sewell | Date | Re: [xsl] Sorting an xml, andrew welch |
Month |