Subject: Re: [xsl] Writing array elements based on a an evaluation of one of the child elements From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 24 May 2006 13:41:32 +0100 |
<xsl:for-each select="." > That is a no-op it youst changes the current node to that selected by . which is the cuurrent node. <xsl:if test="string-length(ACCOUNT-NO/text() > 0)"> ACCOUNT-NO/text() > 0 is a boolean valued expression so string-length(ACCOUNT-NO/text() > 0) is the length of either the string "true" or "false" depending, so either 4 or 5 and then as it's used in a test expression both strings "true" and "false" are coerced to true() (as they are non-zero). You meant test="string-length(ACCOUNT-NO/text()) > 0"> Although that doesn't do what you want as you want to iterate over all the ACCOUNT-NO elements. <xsl:template match = "ACCOUNT-LIST"> I think this does what you want: <xsl:template match = "ACCOUNT-LIST"> <xsl:copy> <xsl:copy-of select="ACCOUNT-LIST[text()]"/> </xsl:copy> </xsl:template> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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