Subject: RE: [xsl] What's wrong with this key? From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 24 May 2006 14:31:19 +0100 |
> So to be bold, how can I correctly create a key expression to > read out all members of a key, or list them in some other way? For <xsl:key name="N" match="M" use="U"/> you can find all the members of the key using select="//(M)". There's no way of finding them via the key itself. (The term "members of the key" isn't actually meaningful, but I think I can guess what you might mean.) Michael Kay http://www.saxonica.com/
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