Subject: RE: [xsl] "not a node item" inside distinct-values From: "Rick Roen" <Rick@xxxxxxxxxxxxxxxxxx> Date: Thu, 8 Jun 2006 10:58:08 -0500 |
Indeed, it is easier to understand and hopefully more efficient. I changed my stylesheet to: <xsl:for-each-group select="item" group-by="@racknum"> <p>Group racknum: <xsl:value-of select="current-grouping-key()"/> Group max: <xsl:value-of select="max(current-group()/@pocketnum)"/> </p> </xsl:for-each-group> And now I get results: <p>Group racknum: 1 Group max: 13</p> <p>Group racknum: 2 Group max: 6</p> Thank you! -----Original Message----- From: David Carlisle [mailto:davidc@xxxxxxxxx] Sent: Thursday, June 08, 2006 9:38 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] "not a node item" inside distinct-values Others have pointed to teh immediate cause of teh error message, but if you find yourself doing this: > <xsl:for-each select="distinct-values(//item/@racknum)"> > <xsl:variable name="rack-num" select="."/> > <xsl:variable name="pocket-num" select="//item[./@racknum = > $rack-num and position() = last()]"/> 9 times out of 10 its easier (and probably more efficient) to do <xsl:for-each-group select="//item" group-by="@racknum"> (also probably //item should just be item) David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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