Re: [xsl] Renaming an element when using copy-of

["Spencer Tickner" <spencertickner@xxxxxxxxx>]

Without seeing more of your code.

<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>

<xsl:template match="source">
<newname>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</newname>
</xsl:template>

<xsl:template match="child_element">
<newchildname>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</newchildname>
</xsl:template>

<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>


As you need to add more changes to element names, just add more
templates to match them as source and child_element above do, and
replace the <newname> and <newchildname> with whatever you want them
to be renamed to.


Spence

On 6/13/06, Chad Chelius <cchelius@xxxxxxxxxxxxxxx> wrote:
> I am trying to copy the contents of an element called <source> using
> a template but I want to change it's name when doing so. This
> <source> element contains several children that I want to carry over
> but I also want to rename them as well. I'm currently using:
>
> <xsl:copy-of select="source"/>
>
> This works but I want to change the name of source. How do I do this?