RE: [xsl] Recursively merge (aggregate) and traverse DOM tre

Your stylesheet needs to include within it an instruction such as

<xsl:apply-templates select="document(@url)"/>

to dereference the links and recursively process the referenced document.

I don't know what this is supposed to be:

<?xml versionfiltered="1.0" encoding="UTF-8"?>

but it isn't XML.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Laky Tang [mailto:tulaky@xxxxxxxxx] 
> Sent: 20 June 2006 03:46
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Recursively merge (aggregate) and traverse DOM 
> trees (XML files)?
> 
> I am trying to recursively merge a tree of XML files and then 
> apply some templates to it. I googled and also searched this 
> mailing list but did not find any help. I hope this is 
> possible using XSLT. Can somebody please point me in the 
> right direction?
>  
> Here is a sample of the input files and desired output. I 
> tried a sample.xsl (see below)which only goes thru the root 
> file, but need help in making it recursively go thru all the 
> linked files as well.
>  
> Thanks in advance,
> Laky, Tang
> -----------------
> sample1.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> 
> <?xml-stylesheet type="text/xsl" href="sample.xsl"?> <a> <b p 
> ="key1" q="2"> xxx </b> <b url = "sample2.xml"></b> <b p 
> ="key10" q ="27">yyyy</b> </a>
>  
> sample2.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p 
> ="key4" q="22"> xxx2 </b> <b url = "sample3.xml"></b> <b p 
> ="key7" q ="37">yyyy2</b> <b url = "sample4.xml"></b> </a>
>  
> sample3.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p 
> ="key5" q="23"> xxx3 </b> <b p ="key6" q ="26">yyyy3</b> </a>
>  
> sample4.xml :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p 
> ="key8" q="24"> xxx4 </b> <b p ="key9" q ="25">yyyy4</b> </a>
>  
> sample.xsl :
> <?xml versionfiltered="1.0" encoding="UTF-8"?> 
> <xsl:stylesheet versionfiltered="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:fo="http://www.w3.org/1999/XSL/Format";
> xmlns:xs="http://www.w3.org/2001/XMLSchema";
> xmlns:fn="http://www.w3.org/2005/02/xpath-functions";
> xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes";
> xmlns:xlink="http://www.w3.org/1999/xlink";>
> <xsl:template match="/">
> <html>
> <head>
> <title>Sample</title>
> </head>
> <h1>
> <center>
> </center>
> </h1>
> <p/>
> <xsl:for-each xml:space="default" select="param"> 
> <xsl:value-of select="."/> </xsl:for-each> <table border="2" 
> bgcolor="yellow"> <tr> <th>P</th> <th>Q</th> <th>text</th> 
> </tr> <xsl:for-each select="//b"> <tr> <td> <xsl:value-of 
> select="@p"/> </td> <td> <xsl:value-of select="@q"/> </td> 
> <td> <xsl:value-of select="."/> </td> </tr> </xsl:for-each> 
> </table> </html> </xsl:template> </xsl:stylesheet>
> 
>  
> Desired output (preferably as a html table):
>  
> P    Q    text
> key1    2    xxx 
> key4    22    Xxx2
> key5    23    xxx3
> key6    26    yyy3
> Key7    37    yyy2
> key8    24    xxx4
> key9    25    yyy4
> key10    27    yyyy
> 
> 
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