Re: [xsl] Eliminating leading zeros

Subject: Re: [xsl] Eliminating leading zeros
From: "Mark Wilson" <drmark@xxxxxxxxxxxxxxx>
Date: Mon, 21 Aug 2006 09:25:16 -0400
Thanks,
98% of my problem was solved by your suggestion. Actually, the full senerio required some additional statements.


I put in a <xsl:if> test to determine whether the optional element <sortedItem> was present or not present (this solved my first set of problems), and if it was, I used an <xsl:choose> for <xsl:when> <sortedItem> contained only digits (this solved my second set of problems) and <xsl:otherwise> when it contained digits together with addition characters, as in

<sortedItem>05 (supl.)</sortedItem>

Without the <xsl:otherwise>, a NaN was returned. Thus my third set of problems, yet unsolved.

If <xsl:value-of select="number(.)" /> renders properly when only digits are present, what would the code look like to render
<sortedItem> 05 (supl.)</sortedItem>
as
<renderedItem> 5 (supl.)</renderedItem>
That is, removing the leading zero in this case.


The actual additional text in <sortedItem> may vary, but the digits always come first and there is always a space after them. The text is usually,but may not always be, (supl.).

Again, thanks for the first bit of help.
Mark


----- Original Message ----- From: "David Carlisle" <davidc@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, August 21, 2006 7:56 AM
Subject: Re: [xsl] Eliminating leading zeros




number(.)


David

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