Re: [xsl] Sort before paging

Subject: Re: [xsl] Sort before paging
From: "Giancarlo Rossi" <giancarlo_rossi@xxxxxxxxxx>
Date: Sun, 27 Aug 2006 11:29:02 +0200
Hi...
I'm sorry

Is the first time using this list...
I need to sorting and paging all the document.

You could find  the xml here:
http://www.lastminutesud.it/test/andata_fco.xml

Using the code below I get an error:

[italian error]
Il foglio di stile non include un elemento documento. Il foglio di stile h
vuoto oppure potrebbe essere un documento XML in formato non corretto.

[english error]
The stylesheet does not iclude a valid element. The stylesheet is empty or
it should be a not valid xml document with a correct format.

Code
-------------------------------------
<xsl:param name="start" select="1"/>
<xsl:param name="range" select="5"/>
<xsl:template match="/">
<xsl:call-template name="positionfilter"> <xsl:with-param name="sortedlist">
<xsl:for-each
select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardL
ist/Outward[position() &gt;=$start and position() &lt; $start + $range]" >
<xsl:sort select="Price/Amount" data-type="number" order="ascending" />
<xsl:copy-of select="."/> </xsl:for-each> </xsl:with-param>
</xsl:call-template/> </xsl:template>


<xsl:template name="positionfilter">
<xsl:param name="sortedlist"/>
<xsl:for-each select="$sortedlist/*[(position() &gt;= $start) and
(position() &lt; $start + $range)]">
'my code
</xsl:for-each>
</xsl:template>

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