Subject: Re: [xsl] function for getting filename From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> Date: 01 Sep 2006 06:59:49 +0100 |
>>>>> "Frank" == Frank Marent <frank.marent@xxxxxxxxxxx> writes: Frank> i'm struggling again and again over this point: is there a Frank> function in xslt that gives me the clean filename of the Frank> processed xml file? like No. it might not be an xml file at all. Frank> 'myfile.xml' 'test.xml' 'anyfilename.xml' Frank> i do *not* need the document-uri. only the filename of the Frank> current processed xml file. But if you have the document URI, and it's scheme is file, then you can get the file name form it. Otherwise, there probably is no file. -- Colin Adams Preston Lancashire
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