Subject: RE: [xsl] Type error with variable as=xs:string using xsl:choose From: "Trevor Nicholls" <trevor@xxxxxxxxxxxxxxxxxx> Date: Thu, 7 Sep 2006 22:42:34 +1200 |
David: In this case you could probably avoid the whole problem as <xsl:variable name="normsrc" as="xs:string" select="replace($xsrc,'^.*/images/','images/')"/> Indeed I will. It makes the intention pretty clear... Thanks again Trevor
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