Re: [xsl] make recursive call

["mary liu" <maryliu99@xxxxxxxxx>]

Thanks Mukul! It is very helpful.

Another question is if I have exception data, like the last 2 records.
I want to genterate like newxml.xml.

oldxml.xml


<ResultSet>
<data_service>
 <Employeeprofile>
<row emp_name="one" org_cd="73700" rpt_to_org_cd="11111"  lev="2" />
<row emp_name="four" org_cd="73656" rpt_to_org_cd="73700" lev="3"  />
<row emp_name="five" org_cd="75425" rpt_to_org_cd="73700" lev="3"  />
<row emp_name="three" org_cd="73723" rpt_to_org_cd="11111"  lev="2" />
<row emp_name="two" org_cd="73708" rpt_to_org_cd="11111"  lev="2" />
<row emp_name="Six" org_cd="73651" rpt_to_org_cd="73708" lev="3"  />
<row emp_name="Seven" org_cd="73632" rpt_to_org_cd="73651" lev="4"  />
<row emp_name="Eight" org_cd="73229" rpt_to_org_cd="73651" lev="4"  />
<row emp_name="nine" org_cd="74023" rpt_to_org_cd="73651" lev="4"  />
<row emp_name="ten" org_cd="73989" rpt_to_org_cd="11111"  lev="2" />

<row emp_name="eleven" org_cd="897750" rpt_to_org_cd="UHFH"  lev="4" />
<row emp_name="twelve" org_cd="3334" rpt_to_org_cd="4456"  lev="2" />
</Employeeprofile>
</data_service>
</ResultSet>


the newxml.xml

So the newxml.xml should be like this:


<ResultSet>
<branch id="one">
     <branchText>one</branchText>
     <leaf>
         <leafText>four</leafText>
     </leaf>
    <leaf>
       <leafText>five</leafText>
    </leaf>
 </branch>


 <branch id="three">
    <branchText>three</branchText>
 </branch>


 <branch id="two">
    <branchText>two</branchText>
     <branch id="Six">
    <branchText>Six</branchText>
    <leaf>
        <leafText>Seven</leafText>
    </leaf>
    <leaf>
          <leafText>Eight</leafText>
    </leaf>
        <leaf>
          <leafText>nine</leafText>
    </leaf>
 </branch>
  </branch>


  <branch id="ten">
    <branchText>ten</branchText>
 </branch>

  <branch id="eleven">
    <branchText>eleven</branchText>
 </branch>

<branch id="twelve">
    <branchText>twelve</branchText>
 </branch>
</ResultSet>



Re: [xsl] make recursive call
Subject: Re: [xsl] make recursive call
From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>
Date: Sat, 26 Aug 2006 22:46:12 +0530

Please try this stylesheet:


<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";;>

<xsl:output method="xml" indent="yes" />


<xsl:template match="/">
 <ResultSet>
    <xsl:apply-templates
select="ResultSet/data_service/Employeeprofile/row[@lev = 2]" />
 </ResultSet>
</xsl:template>


<xsl:template match="row">
 <branch id="{@emp_name}">
    <branchText>
       <xsl:value-of select="@emp_name"/>
    </branchText>
    <xsl:variable name="row1" select="../row[@rpt_to_org_cd =
current()/@org_cd]" />
    <xsl:variable name="row2" select="../row[@rpt_to_org_cd =
$row1/@org_cd]" />
    <xsl:choose>
      <xsl:when test="$row2">
        <xsl:apply-templates select="$row1" />
      </xsl:when>
      <xsl:otherwise>
        <xsl:for-each select="$row1">
          <leaf>
             <leafText><xsl:value-of select="@emp_name" /></leafText>
          </leaf>
        </xsl:for-each>
      </xsl:otherwise>
    </xsl:choose>
 </branch>
</xsl:template>

</xsl:stylesheet>

This when applied to the given XML, produces the desired output.

On 8/25/06, mary liu <maryliu99@xxxxxxxxx> wrote:
Hi,


I have a oldxml.xml file need to be converted to the newxml.xml file.  I can
only convert it to 2 levels and dont know how to make it recursive. I don't
know how deepth it is. My convert file is like this:

conver.xsl


<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform";;>
<xsl:template match="/">


 <ResultSet>
   <xsl:apply-templates
select="ResultSet/data_service/Employeeprofile/row[@lev = 2]"/>
 </ResultSet>


</xsl:template>
<xsl:template match="row">
 <xsl:element name="branch">
 <xsl:attribute name="id">
             <xsl:value-of select="@emp_name" />
  </xsl:attribute>


   <branchText>
     <xsl:value-of select="@emp_name"/>
   </branchText>
    <xsl:call-template name="IterateRows">
     <xsl:with-param name="rows" select="following-sibling::node()"/>
   </xsl:call-template>
 </xsl:element>
</xsl:template>
<xsl:template name="IterateRows">
 <xsl:param name="rows"/>
 <xsl:if test="$rows[1]/@lev = 3">
   <leaf>
     <leafText>
       <xsl:value-of select="$rows[1]/@emp_name"/>
     </leafText>


   </leaf>
   <xsl:call-template name="IterateRows">
     <xsl:with-param name="rows" select="$rows[position()> 1]"/>
   </xsl:call-template>
 </xsl:if>
</xsl:template>
</xsl:stylesheet>




oldxml.xml


<ResultSet>
<data_service>
 <Employeeprofile>
<row emp_name="one" org_cd="73700" rpt_to_org_cd="11111"  lev="2" />
<row emp_name="four" org_cd="73656" rpt_to_org_cd="73700" lev="3"  />
<row emp_name="five" org_cd="75425" rpt_to_org_cd="73700" lev="3"  />
<row emp_name="three" org_cd="73723" rpt_to_org_cd="11111"  lev="2" />
<row emp_name="two" org_cd="73708" rpt_to_org_cd="11111"  lev="2" />
<row emp_name="Six" org_cd="73651" rpt_to_org_cd="73708" lev="3"  />
<row emp_name="Seven" org_cd="73632" rpt_to_org_cd="73651" lev="4"  />
<row emp_name="Eight" org_cd="73229" rpt_to_org_cd="73651" lev="4"  />
<row emp_name="nine" org_cd="74023" rpt_to_org_cd="73651" lev="4"  />
<row emp_name="ten" org_cd="73989" rpt_to_org_cd="11111"  lev="2" />
</Employeeprofile>
</data_service>
</ResultSet>


lev="2" is same level. Then lev=3, lev=4...
every level may have leaves or may not have leaves, like emp_name="two", it
has no leaf.


Attribute rpt_to_org_cd is the value pointing to the parent. for example
emp_name="Eight", rpt_to_org_cd ="73651", its parents' node is same as
emp_name="Seven" and emp_name="nine" which is emp_name="Six" org_cd="73651"

So the newxml.xml should be like this:


<ResultSet>
<branch id="one">
     <branchText>one</branchText>
     <leaf>
         <leafText>four</leafText>
     </leaf>
    <leaf>
       <leafText>five</leafText>
    </leaf>
 </branch>


 <branch id="three">
    <branchText>three</branchText>
 </branch>


 <branch id="two">
    <branchText>two</branchText>
     <branch id="Six">
    <branchText>Six</branchText>
    <leaf>
        <leafText>Seven</leafText>
    </leaf>
    <leaf>
          <leafText>Eight</leafText>
    </leaf>
        <leaf>
          <leafText>nine</leafText>
    </leaf>
 </branch>
  </branch>


  <branch id="ten">
    <branchText>ten</branchText>
 </branch>

</ResultSet>

Is there anybody helping me? Thanks in advance.

Mary