Re: [xsl] Sum in conjunction with string splitting?

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

On 9/8/06, Steve <subsume@xxxxxxxxx> wrote:
> Posted yesterday, but I isolated the problem significantly =)
>
> The snippet below attempts to split the string 'mileage 6' into
> [mileage] and [6] and then store it in $miles (for example).
>
> I am trying to get the SUM of the resulting SPLIT of the nodes that
> match 'mileage'.
>
> I am close. Right now I only get one node, not the sum of all matches.
>
> <xsl:variable name="miles">
>        <xsl:call-template name="str-split-to-words">
>                <xsl:with-param name="pStr"
> select="msxsl:node-set($expenses[substring(expense,1,7)='mileage']/expense)"
> />
>                <xsl:with-param name="pDelimiters" select="' '" />
>                                      <!-- splitting expense at blank spaces -->
>        </xsl:call-template>
> </xsl:variable>
> <xsl:value-of select="msxsl:node-set($miles)/*[2]" /><br />
>
> ====
>
> $expenses example:
>
> <Expenses>
>    <expense>Mileage 6</expense>
>    <expense>cheese</expense> (wouldn't match)
>    <expense>Mileage 10</expense>
> </Expenses>
>
> ====
>
> Desired value of $miles: 16.

With FXSL2.0 one would simply write:

     sum(f:map(f:compose(f:decimal(),
                         f:flip(f:substring-after(),' ')
                         ),
               /*/*[contains(.,' ')]
               )
         )


Or simply use the f:transform-and-sum() function:

     f:transform-and-sum(f:flip(f:substring-after(),' '),
                         /*/*[contains(.,' ')]
                         )


In XSLT 1.0, one can use the "transform-and-sum" template of FXSL 1.x


--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk



> Thanks a bunch,
>
> -Steve