Re: [xsl] xtvd grouping problem (I think)

Subject: Re: [xsl] xtvd grouping problem (I think)
From: "Bob Portnell" <simply.bobp@xxxxxxxxx>
Date: Fri, 8 Sep 2006 14:25:55 -0700
Let me clarify a little. I already have my set of programs in a
variable... call it $hitSet. So that's cool. And the bit from the sort
on down I'd already worked out. Good and good.

I need to get away from any looping based on program IDs. That's my
problem: program IDs are more fine-grained than my search item terms.
So I need to expand up, collecting up all the <schedule>s which have
the program IDs from $hitSet (and so representing each search item
discovery individually)

In pseudocode, my vision is something like
for each member of schedule ( a long list)
   if this member's @program is found among the @ids in (hitSet list)
       push (this member into Keepers list)

But I have no idea if that's possible in XSLT. I have a hunch it is,
and I'm just overlooking a very simple XPath function for the
assignment...

Bob P
simply.bobp@xxxxxxxxx



On 9/8/06, Steve <subsume@xxxxxxxxx> wrote:
On 9/8/06, Bob Portnell <simply.bobp@xxxxxxxxx> wrote:
>     for each search item
>         find the set of programs which have that item
>         convert this to the set of schedule items which have those programs
>         for each in the schedule set
>             sort by time
>             report the show information.

<xsl:for-each $progSet/items[@item=@search]/@prog>
     <xsl:variable name="prog" select="@prog" />
      <xsl:for-each $scheduleSet[@prog = $prog]/@prog>
        <xsl:sort select="@time" />
        <xsl:value-of select="@showInfo"
      </xsl:for-each>
   </xsl:for-each>


> Given a variable $progSet which has a bunch of <programs> in it, how > do I define a $schedSet which has only <schedule> items containing > @program ids from $progSet? > > I've gotten as far as > <xsl:variable name="schedSet" select="//schedule[@program . . {sound > of screeching brakes}? />

Pretty sure I touched on this above. Let me know.

> Please excuse where I've strayed from proper XSLT vocabulary; I hope
> my intent is clear enough despite such lapses of inexperience.

No problemo. Was very well conveyed. =).

-S

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