Re: [xsl] Element name Change for a node

[Senthilkumaravelan Krishnanatham <senthil@xxxxxxxxx>]

Thanks Michael Kay for help.It is so simple to follow and helped me  
great indeed .
Regards.,
Senthil
On Sep 14, 2006, at 12:52 AM, Michael Kay wrote:

> I would do this as:
>
>  <xsl:stylesheet version="1.0"
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
>    <xsl:output method="xml" indent="yes" />
>
>    <xsl:template match="*">
>      <xsl:copy>
>        <xsl:apply-templates />
>      </xsl:copy>
>    </xsl:template>
>
>    <xsl:template match="address/*">
>      <xsl:element name="US_{local-name()}">
>        <xsl:apply-templates/>
>      </xsl:element>
>    </xsl:template>
>
>  </xsl:stylesheet>
>
>  Michael Kay
> http://www.saxonica.com/
>
> > -----Original Message-----
> > From: Mukul Gandhi [mailto:gandhi.mukul@xxxxxxxxx]
> > Sent: 14 September 2006 05:20
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: Re: [xsl] Element name Change for a node
> >
> > Please try this stylesheet:
> >
> > <xsl:stylesheet version="1.0"
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> >
> >   <xsl:output method="xml" indent="yes" />
> >
> >   <xsl:template match="/address">
> >     <address>
> >       <xsl:apply-templates />
> >     </address>
> >   </xsl:template>
> >
> >   <xsl:template match="*[../self::address]">
> >     <xsl:element name="{concat('US_', local-name())}">
> >       <xsl:value-of select="." />
> >     </xsl:element>
> >   </xsl:template>
> >
> > </xsl:stylesheet>
> >
> > This when applied to XML:
> >
> > <address>
> >   <streetAddress>123 First Street</streetAddress>
> >   <city>Sometown</city>
> >   <state>CA</state>
> >   <zip>12345</zip>
> >   <province/>
> >   <country>USA</country>
> > </address>
> >
> > Produces output:
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <address>
> >    <US_streetAddress>123 First Street</US_streetAddress>
> >    <US_city>Sometown</US_city>
> >    <US_state>CA</US_state>
> >    <US_zip>12345</US_zip>
> >    <US_province/>
> >    <US_country>USA</US_country>
> > </address>
> >
> >
> > On 9/14/06, Senthilkumaravelan Krishnanatham
> > <senthil@xxxxxxxxx> wrote:
> > > Hi All,
> > >
> > > I have the following structure in my XML and I want to
> > transform this
> > > all "address" node content to prefix with "US".
> > > Please let me how to create the XSL template for the given input.
> > >
> > > Input
> > >   <address>
> > >    <streetAddress>123 First Street</streetAddress>
> > >      <city>Sometown</city>
> > >      <state>CA</state>
> > >      <zip>12345</zip>
> > >      <province />
> > >      <country>USA</country>
> > >   </address>
> > >
> > > output
> > >   <address>
> > >    <US_streetAddress>123 First Street</US_streetAddress>
> > >      <US_city>Sometown</US_city>
> > >      <US_state>CA<US_/state>
> > >      <US_zip>12345</US_zip>
> > >      <US_province />
> > >      <US_country>USA</US_country>
> > >   </address>
> > >
> > > I do not know how to create the XSL for it to transform.
> > >
> > > Thanks for your help.
> > >
> > >
> > > Regards,
> > > Senthil
> >
> >
> > --
> > Regards,
> > Mukul Gandhi
> >
> > http://gandhimukul.tripod.com