RE: [xsl] outputting <?xml version="1.0" encoding="UTF-8"?>

["Ian Murphy" <ian@xxxxxxxxxxxxxx>]

This was one of the things I tried out before trying the list. My
current header is:

<xsl:output method="xml" version="1.0" encoding="UTF-8"
omit-xml-declaration="no"/>

But it doesn't seem to have had the effect it should have done. I
suspect the dotnet xsl.transform lib I am calling has some option which
overrides this but I can't find it.

Ian Murphy
Integra XP
http://www.integra-xp.com
00 34 94 621 5265


-----Mensaje original-----
De: Abel Braaksma [mailto:abel.online@xxxxxxxxx]
Enviado el: lunes, 18 de septiembre de 2006 13:52
Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Asunto: Re: [xsl] outputting <?xml version="1.0" encoding="UTF-8"?>

Ian Murphy wrote:
> Now the question is, who is responsable for putting this header in
> place? From what I know it should be the .net 1.1 xsl libraries I use
> to do the transform, no? I've been searching the docs and can't find
> any reference to enabling or disabling the production of this header,
> though I could be looking for the wrong thing.
>

I missed on the whole discussion, but to enable/disable the <?xml ...?>
header part, you can do the following:

<xsl:output indent="yes" method="xml"  encoding="UTF-8"
omit-xml-declaration="no" />

But, if you haven't got this statement *and* your method is "xml", the
default value for "omit-xml-declaration" is "no", meaning, that the XML
declaration, by default, should be output by the processor. Setting it
to "yes" will suppress the output of the xml declaration.

Abel Braaksma
http://abelleba.metacarpus.com